Ad
Code
Diff
  • x = lambda n:(i for i in range(n) if not(i%4 and i%6))
    • x=lambda n:(i for i in range(n) if not(i%4and i%6))
    • x = lambda n:(i for i in range(n) if not(i%4 and i%6))
Code
Diff
  • def kube(x, y, z):
        #your code here
        return x*y*z
    • def kube(x, y, z):
    • #your code here
    • return 0
    • return x*y*z