I have tested these keys without success to decrypt your message: agedyropulik politykarenu regulaminowy kaceminutowy koniecmatury arewybuhoki bawoletykiju
Should your message contain the Pound-Sign?
Let's assume the language is English and the alphabet consists of 18 ( = 26 (a, b, ..., z) - 8 (=p r o b l e m t) ) unknown characters. This results in 1.5e12 ( =Binomial(18*18, 6) ) keys. Then around 1.0e13 (=7*1.5e12) words would have to be checked to see whether they are valid English words. Rather difficult, isn't it?
duplicate issue (see below)
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@eb110 I actually agree with you. It should be explained (or at least displayed in sample tests) that:
What would be a better wording, if you would propose one? ^^
I have tested these keys without success to decrypt your message: agedyropulik politykarenu regulaminowy kaceminutowy koniecmatury arewybuhoki bawoletykiju
Should your message contain the Pound-Sign?
Let's assume the language is English and the alphabet consists of 18 ( = 26 (a, b, ..., z) - 8 (=p r o b l e m t) ) unknown characters. This results in 1.5e12 ( =Binomial(18*18, 6) ) keys. Then around 1.0e13 (=7*1.5e12) words would have to be checked to see whether they are valid English words. Rather difficult, isn't it?
Approved by someone
Approved.
This comment is hidden because it contains spoiler information about the solution
Can you add fixed tests to fix this issue ?
Approved!
Approved.
off the topic but can you please answer this question here.
Thank you.
same for all languages
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