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    This comment is hidden because it contains spoiler information about the solution

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    Description:

    If the input array is empty consider it as: [0] (array with a zero).

    But there are no empty arrays in the tests. That's too bad. Because in this case solutions with reduce would not work.

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    The reason of your problem is that you mix up, and seem to miss the difference, between numbers and digit characters. When you do odd = [1,3,5,7,9], then the list odd contains 5 numbers: 1, 3, 5, 7, and 9. When you do number = list(str(sum(arr))), the number list holds characters, for example: '1', '3', '5', '7', or '9'. That's why when you do number[-1] in odd you get no results: because for example '5' is not in [1, 3, 5, 7, 9].

    5 is, but '5' is not. You need to find out what's the difference between '1' and 1, or between '7' and 7.

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    Thank you for the solution

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    This comment is hidden because it contains spoiler information about the solution

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    Because it is not correct.

    Without seeing your solution we do not know why it is not correct.

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    Why my solution doesn't work?

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    I disagree, checking a number's parity is 8 kyu, checking the parity of the sum of all elements in an array is 7.

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    too easy for 7 kyu

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    Thanks!

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    Approved

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    its 8kyu, not 7

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    I think it's okay to keep different types as inputs but the description is really off

    Given a list of integers

    in context of Haskell seems like a literal requirement for the arg to be [Integer] type

    There should be Haskell-specific description clarifying that input is a list of Integral derivative

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    wouldn't it be fine if simply defining the type in the default code? it's quite odd for the solver to specify the type when they don't .. know what it should be

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    Yeah, that's nowhere remotely close to what the kata is supposed to test, which is a problem in itself.

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