Yesn't, Char is an instance of Ord where the characters are ordered by their unicode codepoint. It does not really "threat them as they were numbers" but deep down at some point everything is an int eventually.

wait, Haskell treats chars the same way as if they were numbers? like, he automatically converts char to number like ord() in python?

Of course, I was just commenting because for me, as a mathematician, it was on the first glance confusing that this actually works :D

To be fair, the type definition is Int -> Int, not (Num a) => a -> Int, so a Double would never be allowed into the function.

Note that this definition would not work for Double, e.g. 2.25=1.5^2 would be sent to 2^2=4, because 1.5 gets rounded to 2, although 2.25 is closer to 1 than to 4.

It's not about size. In point-free version cycle "10" will most likely be evaluated only once (even if you don't really need it in this case)

get this error message ... Could not find module ‘HasSubPatternII’

Oh crap, undefined does not have :[] in it ..

length

I looked at that and thought "that's not gonna work". But it does.

Is it reverse that stumbles over that undefined ? I'm still not seeing that, if I'm honest.

The madlad

How about

head (dropFromEnd 1 ('a' : 'b' : undefined)) `shouldBe` 'a'

?

Infinity is not 100000.

If you can't solve it, just forfeit. I can't actually test with Infinity, so please just don't do this.

Oh hey.. I forgot that where was an option