Finally! I'm surprised by how few people used logarithms. However, I'm a little confused as to how this would work where the logarithm returns a whole number. Wouldn't that lead the program to over-estimating?

For instance, if h = 2, window = 1, and bounce = 0.5, wouldn't log(window / h) / log(bounce) return 1, which would then be multiplied by 2 and added to 1, resulting in 3? If I recall, the answer desired by the prompt here is 1, so I'm really curious what I'm missing here, since I was on a similar path as you, but added logic to avoid this scenario.

The same!, but I use reverse=True, select -1

Если честно, я совсем ничего не понял. Ну, да ладно может со временем разберусь.

Didn't get what this &-operator was doing. Can someone explain this to me?
upd Got it

Thanks ;-)

Beautiful :O!!

Cool kata, it leaves a lot of room for different solutions

I'm having the same issue

I got into programming a 3 weeks ago, and this kata was great OOP practice! This site helped me progress really fast