Ad
Code
Diff
  • def myMap(mine):
        l = [i+1 for i in mine]
        return l
        
    • def sayHello(say):
    • say.append("bulbul")
    • return say
    • def myMap(mine):
    • l = [i+1 for i in mine]
    • return l

There can only be one bulbul!

def sayHello(say):
    l = ["bulbul", "8===D"]
    return l