It reduces your loops by 1. v is already the first element of the array (1 * arr[0] == arr[0]), so you can simply skip the first element on the loop. IMHO this is the best solution.
v
1 * arr[0] == arr[0]
append - good solution if result = make([]int, 0, n)
Loading collection data...
It reduces your loops by 1.
vis already the first element of the array (1 * arr[0] == arr[0]), so you can simply skip the first element on the loop. IMHO this is the best solution.append - good solution if result = make([]int, 0, n)