I guess it solution is similiar to mine and it looks good. I have only one problem with that solution that you called integer from array that you are using "i". I don't think you should call array item "i" because it can be confusing. But still good job!

Make sure that there is a whitespace. It's "' '{3}" not "{3}". :)

doesnt work for me :/

Good solution!

Nice, even if it appears having issues with cases in which one of the bounces isn't strictly > of window, like this:
assertEquals(1, BouncingBall.bouncingBall(2.0, 0.5, 1.0));

3 spaces you could use " {3}" instead~

It was 15 months ago, so I asked this question 2 months after I became a member of codewars.
Chill out mate!

Bruh that's the ternary operator.
You are 3kyu and u don't know how to use it?

very nice

I solved that issue by using Math.ceil() instead of Math.floor, and then subtracting 1. This will give identical results in all cases except when the bounce takes you exactly to the window, in which case it'll subtract that bounce out.

• means more than one however ? sign means if more ok if not ok doesnt matter

it checks whether there are more than one whitespace and splits

Why use recursion here? First its useless overhead, second it forces unecessary comparison operations and its not easier to read in my oppinion. Recursion is mostly used to solve sub problems not repeat the same block of code a number of times.