This code does not seem adaptable to any array with any hash. When you use "names = names.map { |name| name[:name] }" you are using the key ':name' based on the test cases. So this solution only works based on the test cases.

The pop will return the last element, and if the element does not exists, they will return this element...

Perfect solution, and very different from mine!

I'm wondering this as well. When there's one name how come the output is not " & Bart"?
I see it works but I'm having trouble understanding why the "&" is not returned since it's hardcoded into the string.

I don't see how this works with 1 name since you are always including the &

I like how readable this is compared to the one-liners.