I laughed (and, tbh, it still deserves the Best Practice vote XD )

i like this logic, bravo man

hacking

Why use reverse, if we can traverse the array from the end?

I must say that it possibly not universal solution, but deffinitely very resourcefully!

that makes two of us, I feel so dumb after I finally get a solution and I submit, someone posts something like this and I feel like a neanderthal. ;D

Are you sure that it is the same code?
This should happens only if the 'nums' was a char[] not a String[];
In the case of the char[] you would need to use result[i] = Character.getNumericValue(nums[i])

It is a short hand if else statment. Each of the statments
(p1 + p2).equals("scissorspaper") || (p1 + p2).equals("rockscissors") || (p1 + p2).equals("paperrock")
are all conditions of the if statament and if any of them are met then the player that wins will be 1.

When it says int p = at the start it is stating what will the 1 : 2 equal after the if statment.

Man I'm surprised that someone actually replied to a 6 year old solution from when I was trolling around on Codewars :)

Aren't you supposed to implement this method on your own?

G E N I U S

using a ternary operator, this is so genius!

nice solution

What the... I neet to drown myself by stuffing my head into toilet..