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There seems to be some issues regarding the expected values of the tests.

It isn't possible for x=6 and y=18, as a and b would be complex

Actually, the solution for the equation is $a=b=3$, so there is a real solution for $a^7+b^7$

For x=5 and y=35, correct answer is 1576.6106018024825 with maximum deviation of 1e-06

The solution for these equations are $a=\frac {5 + 3 \sqrt 5} {2}$ and $b=\frac {5 - 3 \sqrt 5} {2}$, or vice versa, and $a^7+b^7=235625$, not $1576.6..$

Task features symmetrical equations, but sample tests have different output for inputs (1, 2) and (2, 1).

x + y = 6
x^2 + y^2 = 32

A possible non-complex solution is {x = 3 + sqrt(7), y = 3 - sqrt(7)}, or vice-versa.

There's no clear direction as to what a and b should be, leading to multiple possibility for their value. For example, in the case of x = 6, y = 41.

In your result, expected is 12567.813323059147 (I don't know what the a and b for that).

In my result, I got a = 6.3911649915626345 and b = -0.39116499156263407 which qualifies the two equations in the beginning of the description. However, when I try to evaluate a**7 + b**7, it results in 871144.5028025277.

Why is this a duplicate to another beta kata created just yesterday? Do you two know each other?

Initial code is infuriating. Why convert_to_list(obj) and convert_to_int(obj)? Can't you just put the type of the input as argument name? (as list_ or int_ since list and int are built-ins)

One of the test in sample tests asked for wrong answer.

there should be no examples with leading zeroes for convert_to_int for consistency with the other way. i.e., 23 can technically return [0,0,0,2,3]

trivial list filtering/concatenating is not very novel imo

Very similar to this one except the linked one requires segmentation of characters into given portion whereas this one requires incrementing it sequentially

There is only +-1 coefficient before x in random tests