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Lets say i have
spinningRings(6,6)
is the answer:
3
(they just need to be aligned 0)or
6
(they must align 0 at top)?This comment is hidden because it contains spoiler information about the solution
This comment is hidden because it contains spoiler information about the solution
i think this will perform worse as the number gets bigger.
i dunno, but for me using
Math.sqrt
feels like cheating.but yeah, in real world we will use this way.
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if it is valid, how do jumper calls it?
can you describe why this algorithm works?
This comment is hidden because it contains spoiler information about the solution
This comment is hidden because it contains spoiler information about the solution
what is the size of the little squares? sqrt(N) x sqrt(N)?
concise, briliant, unfortunately hard to understand
can anyone please give me some suggestions?
I've done the kata but with huge inefficiency as i create (not calculate) the possible combinations, loop after loop after loop, then i use Array.length to get the count.
any hint please?