clean, but the intital split/filter repetition seems a bit high in performance cost and very reduceable.

chatGpt gave me same answer when i tried to find a better solution

im working on this solution some how i forgot to put'...' in front of arr

nice and beautiful solution!

20 lines? 🙂

Pretty clean, love it

Or you could just use a.localeCompare(b) instead of trying to find the index. Misread that.

I'd say the best say is

[...'abcdefghijklmnopqrstuvwxyz']

omfg i did't even thought about it, its so obvious...

The right hand side of the || is only evaluated if the left hand side is zero (a falsy value). So the sorting prioritizes count (objects with higher count come first), and when both counts are equal, the next condition is used (alphabetical sorting, by src and then by char).

kind of slow tho :c

can somebody explain me, what exactly happening or we doing in the sort after || or after the OR part?

Nice usage of ternary operator and sort method. I learned a lot from this solution, thanks.

I don't understand why you think this is good solution. You have to cycle for every alpabeth character (no matter if it present in the strings) and then you have to loop through each string to check if that character belongs to it. I don't see this as good performance. There is a trend here that nested functions are always the solution and, while they have their beauty, sometimes shouldn't be consider as a choice to solve a problem.

He is rigth.. remember char '-' in the string

thanks dude... and nice solution..