It's grabbing the function's arguments.
It does so by converting the function to a string and testing it against that regex;
The regex is effectively just ignoring everything but the stuff inside '()' of the function definition.
I was writing a step by step, but it wasn't the best anyways, and I deleted it haha.
It's grabbing the function's arguments.
It does so by converting the function to a string and testing it against that regex;
The regex is effectively just ignoring everything but the stuff inside '()' of the function definition.
I was writing a step by step, but it wasn't the best anyways, and I deleted it haha.
I have no idea whats going on with that regex @.@
could someone explain it?