Curious, i find good numbers but there is a gap in the numerotation....???
for exemple 100 in the place 92
The generation of the automorphic number can give more than one for each.
For exemple is done :
1
5
6
25
76
376
625
625
9376
9376
....
is 625 number 6 or 7
or delete one of them

Python 3.7.8 (tags/v3.7.8:4b47a5b6ba, Jun 28 2020, 08:53:46) [MSC v.1916 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license()" for more information.

m= ("""
dfllllll
drrurrdu
rrlruldu
rrrrrrru
""")
type(m)
<class 'str'>
liste=m.splitlines()
print(liste)
['', 'dfllllll', 'drrurrdu', 'rrlruldu', 'rrrrrrru']

no error

The robot anwnser :
File "/workspace/default/solution.py", line 2, in path_counter
liste=m.splitlines()
AttributeError: 'list' object has no attribute 'splitlines'

I still not understood : The begin of my program is :
def path_counter(m):
liste = m.split()

m is a string
The awnser is :
File "/workspace/default/solution.py", line 2, in path_counter
liste = m.split()
AttributeError: 'list' object has no attribute 'split'

curiously no problem with microsoft visual studio ?

it's not very kind...
I learn python
you should learn kindess

liste=m.split()
is not accept when more than 2 lines

I found the solution :
hex_val='1dc41525'
print(binascii.a2b_hex(hex_val))

result=b'\x1d\xc4\x15%'

no backslashe in \x1d ? :-)
\x1d have the value of 1d (in hexadecimal) or 29 in decimal
\x1d is a byte the same with b'0x1d'
i want to change b'0x1d' in \x1d
and then concate with other \x... to make \x1d\xc4\x15\x25\x91\xe6\x09\x59\x04\x99\x15\x29\x0a\x45\x21\x29 for exemple

in hexdump(data) with \x1d\xc4\x15\x25\x91\xe6\x09\x59\x04\x99\x15\x29\x0a\x45\x21\x29 we find 1d c4 15 25 91 e6 09 59 04 99 15 29 0a 45 21 29
Then in the way back 1d c4....is transform in \x1d\xc4.....

No it's in the other way :

transform a="1a" => aa=str.encode(hex(int(a,16))) give b'0x1a' but i can't transform it in b'\x1a' and then concatene with the others bytes

thanck you

Hello,
i don't see how transform 1a 2b in b'\x1a\x2b' because the '\' is forbiden in string (need two \)

It's very curious :
On my computer the anwnser to the test is ["e", "ddd", "aa"] with frequences 7,5,3
The same for the second test

the awnser to the test give me :
Incorrect frequencies: [7, 5, 2] should be [7, 5, 3]. Your output: ['e', 'ddd', 'cc']. One possible output: ['e', 'ddd', 'aa']
Incorrect match: words not present in the string. Your output: ["won't", ' wont']. One possible valid answer: ["won't", 'wont']

????????????

Hello,
i used Try/except of Python

My program give "False" for testing 2544470768F9

but the test says :

Testing for 2544470768F9
It should give an error for invalid input: True should equal False

Is it forbiden to use Try/except ??

OK I don't see :
"It should give an error for invalid input",lambda: luck_check('6F43E8'))
Curious....

The test is not verry clear about "'"

top_3_words(" //wont won't won't "), ["won't", "wont"]) then we keep words with "'" in the word "won't"
top_3_words(" ' "), []) then we don't keep "'"....

If the shift is initially 1, the first character of the message to be encoded will be shifted by 1, the second character will be shifted by 2, etc...

I suppose that :

If the shift is initially 13, the first character of the message to be encoded will be shifted by 13, the second character will be shifted by 14(13+1)or by 26(26+26)

I rewrite my solution and it was the first solution : shift shift+1 shift+2 and so on