The 'A' is variable, basically always equal to 1 unless you need the extra 10 then you can tack it on (10 that is). There is only a few cases where you want the 'A' to be 11.

[ 'A', '7', 'K', '8', '10' ]
expected 46 to equal 36

is this right?

Approved

python new test framework

The aces part left my brain smoking lol........

i thought all aces are considered 1 point. I have already solved the problem, thanks

It's in the instructions:

An Ace can be counted as either 1 or 11.

You choose how to count it to your benefit. Google "Blackjack rules" or click over the link to Wikipedia in the description.

why the {'8', 'A', 'A'} combination is 20 but not 10? where is can read about this rules?

• Ruby 3.0 should be enabled (Refer this & this for more detail)

Simpler than I thought
Thanks for this interesting kata anyway :)

Ooop I hadn't realised these comments are visible by those that haven't solved it!

Cheers man, that gave me a good idea...
Job Done!

Yep. Confused the ["A","A"] test case, with the ["A","2","A","9","9"] test case... My appologies!

Should have known that a Kata thats been around this long wouldnt have faulty test cases that obvious.

Not an issue. The expected result is 12.