It will be Maximum stack overflow

0.0.0.0 Is still a IP address ??

[https://en.wikipedia.org/wiki/0.0.0.0]

In the context of routing, 0.0.0.0 usually means the default route,

"use strict";
function validBraces(s){
	var stack = [],
		matchMap = {
			'}': '{',
			']': '[',
			')': '('
		};

	for(var i=0,l=s.length; i<l; i++){
		var s1 = s.substr(i, 1);
		var stackTop = stack[stack.length-1];

		if(stackTop === undefined){
			stack.push(s1);
			continue;
		}

		if(stackTop === matchMap[s1]){
			stack.pop();
		}
		else{
			stack.push(s1);
		}
	}

	return !stack.length;
}

Notes

• http://www.bowlinggenius.com/
• http://www.csa.edu.hk/~pe/bowling/means.htm

The error message for this test case is too low.

Value is not what was expected ???

"use strict";

var chained = function(functions){
	var index = 1;

	return function(){

		var prev_return = functions[0].apply(null, arguments);

		do{
			prev_return = functions[index].call(null, prev_return);
		}while(++index < functions.length);

		return prev_return;
	};
};

var tmpl = el == "comment" ? "<!--txt-->" : "<el>txt</el>";
tmpl.replace(/el/g, el).replace(/txt/, txt);  // Would it be better?  1: do not  need to transfer the special ·$·  2: second regular do not need global setting;

// btw: my english is poor. so l am sorry ！  l hope you can understand