I think, this solution is not iterating through the alphabet. It gets the binary value for each character in s, and substracts the binary value of a (?a).
which is the mathematical thinking behind? I was creating 2 iterations to be able to substract each couple of elements and then add them together. Thanks,
hi, regarding this part:
|> Kernel. -(Enum.sum(a)) -> is "Kernel." represents the sum of
the elements raised to the power of b of the list? thanks for the explanation.
I think, this solution is not iterating through the alphabet. It gets the binary value for each character in
s, and substracts the binary value of a (?a).woops, replied to wrong comment, how to delete?
which is the mathematical thinking behind? I was creating 2 iterations to be able to substract each couple of elements and then add them together. Thanks,
hi, why is the convert using this symbol "&"? I thought we just need to call the function by its name and with its arity.thanks for the explanation :)
how do I know here that I am iterating through the alphabet? :) thanks for the information.
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hi, regarding this part:
|> Kernel. -(Enum.sum(a)) -> is "Kernel." represents the sum of
the elements raised to the power of b of the list? thanks for the explanation.