Ad
  • Default User Avatar

    Hi, FrankK! Thanx a lot for you attention to my solution. U R right, but I was wondered when I have recieved your comment and Ive tried to submit this solution again. As you already know the EachNumberOnCardIsUnique() test was failed for 34 times (but the 35-th wasnt,LOL). When I tested my solution for the first time, I saw the green-colored frame and just clicked "Final Submit" without any attention to tests. (I really pretty lucky person!)
    So random in .NET isn't random enough, you know and it can`t solve the unique numbers problem. But the shuffle can! (The Fisher–Yates algorithm). So link to my new solution: http://www.codewars.com/kata/reviews/566d5e980bdf235503000023/groups/57558befbe106bc9820006e7