That´s good point.
You can always use isqrt
I was thinking of this but with regex is faster.
Similar to mine, I only added two return statments for when a ==b and b = []
Bravo!
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That´s good point.
You can always use isqrt
I was thinking of this but with regex is faster.
Similar to mine, I only added two return statments for when a ==b and b = []
Bravo!