Ad
  • Default User Avatar

    Problem: (15, 12, 20, 25)
    Factors: (15 = 3 * 5, 12 = 2 * 2 * 3, 20 = 2 * 2 * 5. 25 = 5 * 5)
    Unique factors: (2, 3, 5) ==> (2 is in 12, 20; 3 is in 15, 12; 5 is in 15, 20, 25)
    Result: (2, 12 + 20)(3, 15 + 12)(5, 15 + 20 + 25) = (2 32)(3 27)(5 60)

  • Default User Avatar

    Part of the problem is to figure out how to deal with the problem. Though, sometimes the servers are just busy.

  • Default User Avatar

    The main reson that the problem is ranked 3kyu is that you have to deal with the timeout problem.