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Just thinking that "loop the same long string 26 times" already is O(n).
unnecessary variable
сBc the office value always needs to be incremented and should therefore not be included in the conditional code.
the home value is only reduced if an umbrella already was waiting there to be taken with.
Yes, totally.
We can do in O(n) if we first count the string chars and later do the check.
Is someone able to explain why this works if you don't use curly brackets on the if (home) and (office) statement but works if you leave them out?
eg:
if (home) {
home--
office++
}