It's short, but it's pretty slow. The ort fonction has a complexity of O(NlogN), where as you can resolve this is O(N) just by going through the list once and comparing elements two by two.

It doesnt work for '1234\n' (says True). Will have to use \A and \Z, not ^ and $

thank you very much. I had no prior familiarty with regex and tbh I'm still a total noob in this whole programming think. thank you for the effort tho. It was really helpful and informative.

I don't get it at all

damn regexers always shining through everything ;D

Cool, two good solutions for this problem. Thanks guys!

no idea how you did that cool link stuff

you mean like this?
Like this: [title](https://www.url.com) -- markdown syntax

awesome, just found it in the documentation also
https://docs.python.org/2/library/re.html#raw-string-notation

no idea how you did that cool link stuff

raw string

noob here, what does the r in the beginning stand for?

why would this not match "00000000". Its supposed to match string that start and end with a four or six digit number right? I don't get how it would match strings having length exactly equal to 4 or 6

Yeah, python re right now apparently matches the newline with $ and doesn't reject. I had to add to this solution a special condition to return False if there was a newline in the pin, kind of an ugly hack.