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    Description has to state explicitly what to do with names with multiple occurences of common letters.
    Take the following example:

    show_relationship('KEVIN', 'ANN') == "Enemies"
    KEVIN and ANN have character `N` in common.
    You must cross out all Ns in both names: 1 in KEVI~N~ and 2 in A~NN~.
    After this step, only 5 letters remain.
    
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    I think there's a problem with the randomized test. Cause it says on the log:
    HSREBQTK
    FLLCG
    13
    1
    We get the value 1 which obviously corresponds to "Friendship" but an error occurs and says:
    expected:<[Siblings]> but was:<[Friendship]>
    although on previous randomized test with the same result:
    KRK
    BOOZJDTZVI
    13
    1
    There is no error
    Please fix this.

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    This comment is hidden because it contains spoiler information about the solution