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Wow, thanks! That explains it.
The problem is rather that the way the perfs are measured is biased ("like usual"...?)
Considering the inputs used, the VERY GREAT MAJORITY of the outputs are -1. That means that what is measured is actually:
So, yeah, v2 is ofc a tiny bit slower.
Now, if you try with a perfect square as input for each call, the result will be the opposite:
Wow, this brings me back :-)
Checked the code, the difference is still present, and the first option is faster.
I'm not sure why exactly, checked the opcodes using
dis.dis
, and figured that the only difference is thatis called for the first one, and
for the second function (same opcodes omitted).
So it looks like storing a value is more expensive then calling a function.
I know that this is old, but why is it slower? Does the assignment really add more time than recalculating the sqrt?
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