The second bonus value would be 1. So, you'd count 10 for the strike, 10 for the bonus on the strike, 10 for the spare (9/) and the next ball rolled as a bonus on the strike. So imagine a game if the first three frames looked like this:

X 9/ 23

So, the X would be 20 points (10 + 10), the 9/ frame would be 12 (10+2), and the 23 frame would be 5.

I am less impressed: it fails horribly when parentheses are nested like in 2^(3*(1+4)+1).

very nice piece of work

First and foremost, i want to give kudos to all of you guys that has completed this keta ahead of me, you guys are some baddass genuis. But the guys that provided this solution, i wish i could come tap from your brains a little loll.. like this is so crasy and amazing, it took me a whole lot of time (days) to complete this keta, i almost gave up but eagerness to see other people's possible solution for this keta makes me to strugle until i passed the advanced tests of this keta. once again kudos to those that solved this keta and the person that created this keta, i appreciate extreme coding like this

wow... thanks, now this is very clear, never understood that next two miles of a thing until now,
thanks once again

Write the function that parses the mileage number input, and returns a 2 if the number is "interesting" (see below), a 1 if an interesting number occurs within the next two miles, or a 0 if the number is not interesting.

11209 + 2 = 11211 <- (The digits are a palindrome)

The same for 109 (111 matches the "Every digit is the same number" criteria too).

please am having real problem understanding this keta, why does isInteresting(11209, [1337, 256]) return 1, i really don't understand.
and why is 109 return 1, someone should please explain this to me thanks

am still yet to understand this challenge completely, what will be the second bonus value to be added to 10 when you have 'X' followed by '9/'.
As in, is (10 + (9 + ?))

Masterpiece, guy you are smart, i love the smart work