You need to add a digit only when it's needed, like from 9 to 10 or 99 to 100. In the cases you mentioned, there is no need to add one, only keep the same amount of digits. Not a kata issue.

Attention: If the number has leading zeros the amount of digits should be considered.

You expect 'foobar00' to be incremented to 'foobar01', then you expect 'foobar099' to be incremented to 'foobar100'. 'foobaar001' should be incremented to 'foobar002'. Retain '0's in some and lose them in some other cases. Do not randomly design Katas just because you've to. Let there be some logic.

PS: I used Python3

I will say that is a bit to hard for 5 Kyu

Haskell translation

My solution is ugly as hell but it was fun to code it :D

lolol

Your code fails several sample tests. The kata is fine, debug your code and fix it. Not a kata issue. Read the post below too.

'foobar1' should equal 'foobar01'

Make it make sense....... next

Thanks for clarifying 👍

In 'foobar0100' should equal 'foobar100' the first value is what your function returned, not the input. To see the input, print it.

I got 'foobar0100' should equal 'foobar100'
...but shouldn't it be 'foobar0100' should equal 'foobar0101' instead?

"foobar00" turns into "foobar01" because the end result after the string was incremented was 2, which did not take up both digits. If it was "foobar09", then it would turn into "foobar10", because the result now takes up both zeros which were in the input. In the case of "foobar099", 99 turns into 100, meaning it now takes up 3 digits. In "foobar099", there are 3 numbers at the end, so you would not include the extra 0 after incrementation.

Documentation is your best friend too

OP solved it, closing