Given n (integer > 2) write the function comp(n) (cmp in COBOL) returning the number of times where a term of u is less than its predecessor up to and including u[n].

As u[n] and n are very different numbers, so "terms of u up to n" are very different from "terms of u up to u[n]".
Didn't attempt this kata earlier, but I also noticed this.

Fixed!

Is it better now? I have re-saved files.

Same problems

Same problem, please fix it, been stuck here twice...

I think that n and u(n) being so "closely" related that saying "going to n" in the u sequence (... where a term of u is less than ...) or "going" to u(n) is the same, no? So I consider the issue as closed. If you don't agree please tell me. Thanks for your post.

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