the real mvp here, good call that it's bitwise via &

I see. Thank you.

Sergio, this returns true when divisors x and y leave the same remainder, right?
e.g. (11 % 2) == (11 % 5) // (1 == 1) true
but 11 is divisible by neither 2 nor 5, and should return false.

Oh thanks i didn't even think about it as unsafe. Just learned it from 'reverse string challenge' with limited characters. And this kumite is honestly, but a test. Was wondering what is this, found out after submitting. I'll find a way to delete it, i guess.

You basically defined a function without any declaration. I feel like you should know the many dangers involved with that practice. Check out this link for more information.

https://www.sololearn.com/Discuss/2191625/javascript-arrow-functions-with-and-without-const

Wanted to extend the idea of using default parameters. I wish I could keep the spread operator, but it must be the last, and default params are set left to right.

In case anybody misread like I did:
"sum of the integers to the left of N is equal to the sum of the integers to the right of N"

I interpreted this as sum of N from the left == sum of N from the right, and I couldn't understand why the first test failed on [1,...,1] which returns 0 (in my incorrect code).

Read carefully!
Thanks for the kata.

Why not just return everything on the right side of the || operator? I don't understand what the comparison to !str gets you. Halp please.