https://www.codewars.com/kumite/5c629522bee54342d8b05dc9?sel=5cbbcc8c7cfcad001a1263ed

Rust translation

Added to description

Rust translation

Rust translation

I've finally found the button. Feeling a little stupid. Should I approve fork or just give you link to it?

Fork

Solution that disallows function from function calling passes the test so you can assume it's disallowed to call one function from another

@GiacomoSorbi Well, I don't realize how to fork Kata. Maybe I have broken something trying to fork. Do I need to solve it in original language to fork? BTW how to find out which one is original language and which are translations? Wiki is not so much helping in understading Codewars interface.

the only variable names allowed in the function body are those declared by the arguments list

Or it means that I cannot call one function from another?

Can function change arity after overwriting? I mean if I have
> fn f a => a
> fn g a b => a + b
> fn F a b => f g a b
then F = f (g a b); but if I'll overwrite f and g:
> fn f a b => a + b
> fn g a => a
then F becomes F = f (g a) b and that breaks AST tree for F. When I started to code I thinked that if we have
> fn f a => b
and then we have
> fn g a b => f a b
on input we should return error, but now I'm not sure.

Should I store functions as strings and recompile them at each call? In that case I'll need to accept almost any function as I cannot correctly detect another function calls in it and then return error only when function is used; or should I check function correctness when it's provided to me?

sort in Rust does not return anything so you can not compare a1.sort() with a2.sort().

Rust translation

Well, I'm asking 3 years old question