validWord(['x','ts','sqx','xtgk','xupq','qy','qyv','x','oow','owy','tvbf','ux','xewuxte','xtewx','xk','f','o','y','pmusqa','sqamq','qvw','wz','zwfa','farx'], 'xtsqxtgkxupqyqyvxoowytvbf')

x, ts, xtgk, xupq, qy, qyv, x, oow, y, tvbf

полностью согласен)
тесты нормально проходят, а потом начинается свистопляска

ye, надо других тянуть за собой)

О, а вот и ты с rss)

Такое чувство, будто кейсы писали , ударив кота головой об клаву..)

'ab' + 'bc' does not equal 'abc', while 'a' + 'bc' does.

yeah actually i removed l from the outer loop though it had no effect and m just accumulates the words that are present in the dictionary
but for cases like

valid_word(['a', 'bgkol', 'a', 'k'],'aakbgkolbgkol')
valid_word(['ab', 'a', 'bc'],'abc')

it isn't working!

l=0
for o in range(0,len(word)-l):
  
  ...

  l += 1

What you are doing with l has no effect on the for loop, in case you are relying on that somehow. You might as well write for o in range(0, len(word)):...
Also, m just keeps accumulating letters without discrimination. In the end it will simply be a concatenation of the input sequence.

this is the code above
its not passing for test cases like these:

print(valid_word(['a', 'bgkol', 'a', 'k'],'aakbgkolbgkol'))
print(valid_word(['ab', 'a', 'bc'],'abc'))

kindly review it Thanks!

Please use the spoiler tag if you are going to post solution code (even non-working) in the discourse.
Also, if you decide to post code, use markdown formatting:

```

your code

```

Otherwise, we can't make heads or tails from what you wrote (indentation matters in python).

also faced this problem. 1 test fails. Not clear logic of kata. Nobody can answer?

done (hopefully without me putting more mistakes in the random tests...)