I feel like I'm taking crazy pills reading this description. At least have a few more tests to help connect the dots if you can't write good instructions.

hahahahhahahaahaah

haha I knew there had to be a faster way while writing out the switch statement and you found it!

I love it

firstMin gets the lowest number in the array. secondMin gets the second lowest by calling Math.min over the filter method which returns a new array w/o firstMin. Funny way to do it. Best way is to sort the array lowest to highest with the sort method and then simply add the first two indexes in the array.