This kata has no useful directions. Can we please get rid of it? Surely, there are more sensible variations readily available.

This is a fun solution

I think I'm in love <3

Thx! Good old days of fun programming.

I'm digging your check4uniqueness helper fxn!

There's no such thing as self-documenting code.

Come down from your ivory tower. Code can be elegant, but a single function is not itself art.

A function, or even a library of functions, is a tool. Comments and documentation are how we explain to future users how best to implement whatever tool we've created.

Great comments <3

so MoOse and moose would be treated the same way

Test for "moose" expects false. Test for "moOse" expects false. Relevant assertions in tests are:

assert.strictEqual( isIsogram("moose"), false );
assert.strictEqual( isIsogram("moOse"), false, "same chars may not be same case" );

Doesn't this mean they both behave the same way? What is different about them?

The tests expects false, I don't know what you're complaining about, the test is fine, you're wrong.

assert.equal( isIsogram("moOse"), false, "same chars may not be same case" );

That is the test, if it was be case-sensitive as you claim, it would expect true because o and O would be considered different letters, but it isn't.

Please reread what I wrote and re-check your tests. As many other users have pointed out, that test fails for them, as well. Case insensitization would mean that the case wouod be ignored, so MoOse and moose would be treated the same way. That isn't happening as it should be; it's not working as intended. Check your work.

Please read the definition of case insensitive here: https://en.wikipedia.org/wiki/Case_sensitivity

In case-insensitive, uppercase and lowercase letters are the same, and that's what the test asks.

I would appreciate some explanation from you why you consider my answers wrong, and what is the error in tests you are complaining about, because I think I am missing something:

• The word moose is not an isogram, because the letter o occurs twice.
• The word mOose is not an isogram, because the letter o occurs twice, with differend case (lowercase and uppercase).

The occurrence of letters should be done in a case-insensitive way, i.e. both lowercase letters and uppercase letters contribute to the count of occurrences. And this is how it works in JavaScript translation. So, what exactly you think is wrong?

There are absolutely ways to ignore casing here. Unfortunately, one of the tests written requires case sensitivity, so your function might be perfectly correct and still fail to clear this kata.

The instructions state that the function should be case INSENSITIVE, but one of the tests requires case sensitivity (i.e.: "MoOse === moose" // false;).