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    This comment is hidden because it contains spoiler information about the solution

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    a = [[1], [2], [3]]
    b = [[1], [2], [3], [4]]
    (a & b).size # 3
    a.size # 3

    a = [[1], [2], [3]]
    b = [[1], [2], [3], [1]]
    (a & b).size # 3
    a.size # 3

    But a is not the same as b.

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    This is VERY simple kata.
    If kata is close to katana, then this task is closer to knife)