I salute you sir! :)

You start by cubing every number (n * n * n). Then add the numbers together IF they are odd numbers. Then return the sum of the odd numbers.

so if your numbers are A, B and C:

(A * A * A) = odd1
(B * B * B) = even
(C * C * C) = odd2

Answer would be odd1 + odd2.

Sorry if I've confused things further

Hi , english is not my first language so I didn't get this part "odd cubed numbers" . Lets say for one of test case I got 4 as a "sum of odd" number, if I cube it than it will be 64 , which is incorrect. can you please explain me this?

You will sum the odd cubed numbers, as it says in the title.

I dodn't get it , can anybody please explain me in a easy way?

First, If there is any non integer in array than return None.

Second, I will sort all odd number from array. Then I will sum up the array , than what?