No, that's not what the kata asks, the number can be even or odd (it doesn't matter) what needs to be odd is the number of times it appears in the array.

i did benchmarking on code speed. As i see, this is faster than 'one line solution'. Please correct me if i am wrong.

No idea why i put $reserverWords tag :D it should be $reverseWords :D

wow perfect!

ruby random tests are giving wrong result.

ezarV
["ezart", "Denguil", "lbart", "Galman", "andar"]
Expected: "zart", instead got: "ezart"
there is even no "zart" in the array.

Log
elezrt
["Earth", "elezart", "Denguil", "Gamilas", "halbart"]
Expected: "ezart", instead got: "elezart"

Ah, I see. I misread the output. Thank you.

Not an issue, the first value is what your function returned, not the input value, for the first one, the input was "foobar99". If you want to see the input value, print it, it'll appear above the test result.

I'm solving on Python. The logic I'm seeing in the tests seems to me internally inconsistent. Examples:

'foobar00' should equal 'foobar100'
whereas in the sample tests: Test.assert_equals(increment_string("foobar00"), "foobar01")

I'm also seeing:

foobar10' should equal 'foobar01'
shouldn't this be 11??

Thanks

Hi, just let you guys know: Don't forget this extra examples:
"ca9t0457"
"ca9t0999"
"ca9t9999"

also these:
"00456"
"ca9t"
""