The return statement(s) do the following:

1: If o[v] is falsey (i.e. not an array in this case), set o[v] to an empty array.

This ensures o[v] is always an array before the next statement is processed.

2: Push a into the array at o[v].

Now that we're sure o[v] is an array we can safely push a into it without any checks.

3: The comma operator evaluates all statements separated by them (regardless of return), and returns the final value. In this case the final statment to be returned is simply o;

This line is a more terse way of writing:

if (!o[v]) o[v] = [];
o[v].push(a);
return o;

I'm a little confused by the return line. Can someone further explain? More explicitly why is it "o[v] = o[v]" and I don't understand the ", o". Thanks!

Fair point (:

Don't know if the description updated, but it at least returns a falsy value.

Doesn't this not handle the case of phoneNumber property missing and returning false in this case?