I see it now, thanks to your comment I was able to come up with a solution that solved this kata, it is probably not the best solution but I will try to refactor and improve it. Thanks a lot!

@lazy(-2)
def f():
    return 56

print([f() for _ in range(10)])

I think you agree it shouldn't do this:

[56, None, 56, 56, 56, 56, 56, 56, 56, 56]

For i=2, j=5 it should be a normal function (ie. 56). And the test case should support that. The asserted value is found with val = 56 if j%i else None, which evaluates to 56.

Could you post the solution you are trying to make work?

Aside from a small bit of syntax sugar, it's not very specific to python:

@lazy(2)
def f(): pass

is equivalent to:

def f(): pass
f = lazy(2)(f)

Hello, I've been trying to pass the test cases however I'm facing some errors in the negative number situation.

For the input with @lazy(-2) and i = 2 and j = 5 (that is the 5th call) it is saying that it should be None.
However, the following calls passed:

• 2 1 56
• 2 2 None
• 2 3 56
• 2 4 None

The next is the one that I described before, should it really be None? Since it the 1st call after a lazy call and n == -2