I don't understand how to round up the minutes. This command does not work:

LocalTime time = LocalTime.of(d.getHours(), (d.getSeconds() < 30) ? d.getMinutes() : d.getMinutes() + 1);

Please tell me how to round up the minutes?

Thanks! I realized my mistake! I will have to solve using a different algorithm.

Try printing the needle and think about what would happen with your pattern with that particular input.

Please read this: https://docs.codewars.com/training/troubleshooting#post-discourse

Tell me, what's wrong with my code? The problem is only with the test: nonCharTest.

My code here:

RegEx is ok. Delete ^ and $.

It was very interesting and exciting!

Kruto!!! 😎

Yes, this was the first solution. I didn't like it either. Then I corrected it to the flag. Thanks for the comment! 👍

Yes, this was the first solution. I didn't like it either. Then I corrected it to the flag. Thanks for the detailed comment! 👍

The "a[i] = 99999999;" line is avoidable by using a flag like "boolean present = true"
but even then, the loop keeps going until the end.
Is fixable by doing something like "if ((a[i] == b[j]) && !present)" but it is so unreadable.
The best way, I think, is to just put the inner loop into a new function isPresent() which takes a[i] and b as parameters, instead of "a[i] = 9999999" the function would return true, and would return false instead if the loop ends.

Thank you fellow Human!

What the hell is this?! LMAO how's this a correct solution