Don't use .replace() without third arg, cause python will continue to search another one '0b'.

Me too.

I was looking for a simple way to strip the 0b from negatives

This is exactly the solution I just made, and it gave me a timeout error.

I was thinking much the same as you with this one.

I have the same issue. 46 passed, 1 failed...
Do you found a solution?

What's the hell with "zqdrhpviqslik" in last case?

Yes the return list is ordered in some way. The puzzle(?) is to figure out the order :)

(it's not that hard, really)

This is my output:
[[], [1], [2], [1, 2]] should equal [[], [2], [1], [1, 2]]
Is that means the return_list should be ordered?

Maybe "for i in range(-l-1,l)" is better.