Awesome

I be so excited to complete a challenge with my 32 lines of code then come here and see this TT_TT

Really clever, thank you for the insight.

Genius!

very nice!

I did not understand at first so had to go step by step on paper.

first top voted solution that is really cool in a while

Wow, nice and elegant aproach, but you should use '===' instead of '==' to compare left and right as we intend to compare their numerical value so including type aswell ( in your case "false" would be equal to "0" etc ), and I personally am not a fan of using vars ( "let" and "const" would be more elegant )

Linq is just using someone else code.

And here I am, slicing up the array like a madman with a rusty cleaver...

But there is an index that will make it work. It's 0.

// index 0: [-10, -10, 20]
left = 0;
right = -10 - 10 + 20 => 0;

On index 0 left and right values are equal.

So smart!

It should be noted that in the detail, m > 2.

fun kata and still reasonable best practice.

yeah nice, but it's missing the case in which both a and b are negative

Ok, after seeing this I'm embarrassed of my solution. Genius!