I am still confused, here is how i look to this:

Example 1:
     1 ##############      1 ############## 
     2 #        \   #      2 +--------\   # (2, 0)? or (1,0) if starts with 0
     3 *   \        #  =>  3 *---\    |   #
     4 #            #      4 #   |    |   #
     5 #   \    /   #      5 #   \----/   #
     6 ##############      6 ##############
       12345678901234 = 14 
Example 2:
      1###*###      ###*### 
      2#/ /  #      #/-/  # 
      3#     #  =>  #|    #
      4#     #      #|    #
      5#\    #      #\----+ (5,7) or (4,6) if starts with 0
      6#######      #######
       1234567 = 7

Am I misunderstanding something here?

How first answer of is equal to (0,1)? Isn't it (1,0)?

Describe(exit_from_maze_tests) {
  It (passes_example) {
    Board m {
      "##############",
      "#        \\   #",
      "*   \\        #",
      "#            #",
      "#   \\    /   #",
      "##############"
    };
    Assert::That(exit_from_maze(m), Equals(Result({0, 1}, 22)));
  }

The same second example: it should end on (5, 7)! how it is (6,4)?

 It (passes_second_tests) {
    Board m {
      "###*###",
      "#/ /  #",
      "#     #",
      "#     #",
      "#\\    #",
      "#######",
    };
    Assert::That(exit_from_maze(m), Equals(Result({6, 4}, 10)));
  }
};

I am totally confused, with how answers have gotten? Can you explain me, please!

If there is no help, where i can find some hints?

Checked the code, answers is correct, however output says:

Expected: equal to another value

Actual: some value

Havent' seen that type of question in the comments bellow.

Thank you very much for quick and comprehensive reply. I do appreciate that!

Can anyone help me, i have this error "UndefinedBehaviorSanitizer:DEADLYSIGNAL...". I have no clue why.

P.S. Below said, that return type dynamically allocated string, when there is just string type function. Am I missing something?

I am returning simple string type.