You start by cubing every number (n * n * n). Then add the numbers together IF they are odd numbers. Then return the sum of the odd numbers.

so if your numbers are A, B and C:

(A * A * A) = odd1
(B * B * B) = even
(C * C * C) = odd2

Answer would be odd1 + odd2.

Sorry if I've confused things further

Approved! :)

If you check my solution you will realise something is wrong with your code mate :)

Perfect Kata. Very well written description. 11/10

Accepted - Thank you! :)

No problem! I have added a test that equals zero into the test suite now :)

It needs 10 positive votes. (currently at 8) :)

There is a syntax error in the JavaScript example tests

Thanks for the feedback. I have added another test case which equals 0 but I'm not sure if this has solved your issue.
The Kata is meant to be relatively easy and I am happy for both 0 or undefined to work.

Let me know if you have any suggestions.

Thank you!