Description Suggestion JavaScript
If the input array contains anything other than integers, then return undefined.
Iterate through the array cubing each element meaning e³ or e*e*e.
Grab only the odd cubed elements and return the sum.

Find the sum of the odd numbers within an array, after cubing the initial integers

but

The function should return undefined/None/nil/NULL if any of the values aren't numbers

so, what if number is float (not equal to its integer part)? It is a number, but it is not an odd number (even or odd are defined only for integer)
Seems like, text might be
"The function should return undefined/None/nil/NULL if any of the values aren't integers"
and there must be any test with float (at least there are none of those in python version)

y, errors in test:
assertEquals(0, FindOddCubes.cubeOdd(new int[] {-3, -2, 2, 3})); Must be -19(-3^3+2^2=-19, not 0); expected:<0> but was:<-19>

Maybe it's just me, but I found the wording "the odd numbers" confusing. I thought it meant the odd array entries (ie the 1st, 3rd, etc). It was even more confusing because the first test case gives the same answer. Maybe shuffle the the numbers in the first test case, or make it clear you mean the numbers that are odd.

I saw some of the "correct anwsers" and they should not be accepted.
Please, someone write this test:

  Test.assertEquals(cubeOdd(["12","9"]), undefined);

Edit:

This chanllenge needs to be rewriten if you really want to return undefined if any of the values aren't numbers.